A=23−25+21083−85+810+12
A=(23−25+210)4.(23−25+210)+12
A=14+12
A=34.
Ta có: A=34<44=1.
Vậy A<1
A=12.517−1314.517+15119−1068+2614.517−15238
=12.517−1314.517+3.57.17−2.54.17+2614.517−3.514.17
=12.517−1314.517+37.517−12.517+2614.517−314.517
=517.(12−1314+37)517.(−12+2614−314)
=12−1314+37−12+2614−314
=714−1314+614−714+2614−314
=0141614
=0
Giá trị x thỏa mãn 113:(12x−53)+1=19 là:
113:(12x−53)+1=19113:(12x−53)=19−1113:(12x−53)=−8912x−53=113:−8912x−53=113.−9812x−53=−33812x=−338+5312x=−9924+402412x=−5924x=−5924:12x=−5924.2x=−5912..
Vậy x=−5912.
Ta có: 37+17:x=314
17:x=314−37
17:x=314−614
17:x=−314
x=17:(−314)
x=17.14(−3)
x=−23
Vậy x1=−23
* 57+27:x=1
27:x=1−57
27:x=27
x=27:27
x=1
Vậy x2=1 .
Do đó:
x1+x2=−23+1=−23+33=13.
+) x:(−2115)+312=−34
x:−3115+72=−34
x:−3115=−34−72
x:−3115=−34−144
x:−3115=−174
x=−174.−3115
x=−17.(−31)4.15
x=52760
Vậy x1=52760
+) 511+611:x=2
611:x=2−511
611:x=2211−511
611:x=1711
x=611:1711
x=611.1117
x=617
Vậy x2=617
Do đó:
x1+x2=52760+617=89591020+3601020=93191020.
Ta có 13x+25(x−1)=0
13x+25x−25=0
13x+25x=25
x(13+25)=25
x.(515+615)=25
x.1115=25
x=25:1115
x=25.1511
x=2.155.11
x=611
Vậy x=611 thoả mãn.
Ta có: \left( {3\dfrac{5}{7}x - 1\dfrac{5}{7}x} \right) - \dfrac{1}{3} = \dfrac{2}{3}
\left( {\dfrac{{26}}{7}x - \dfrac{{12}}{7}x} \right) - \dfrac{1}{3} = \dfrac{2}{3}
\left( {\dfrac{{26}}{7} - \dfrac{{12}}{7}} \right)x - \dfrac{1}{3} = \dfrac{2}{3}
\dfrac{{14}}{7}x - \dfrac{1}{3} = \dfrac{2}{3}
2x - \dfrac{1}{3} = \dfrac{2}{3}
2x = \dfrac{2}{3} + \dfrac{1}{3}
2x = 1
x = \dfrac{1}{2}
Vậy x = \dfrac{1}{2} thỏa mãn.
Gọi {x_0} là giá trị thỏa mãn \dfrac{{-1}}{{12}}:x-\dfrac{5}{4}=-1\dfrac{1}{3}, kết luận nào sau đây đúng:
\begin{array}{l}\dfrac{{-1}}{{12}}:x-\dfrac{5}{4}=-1\dfrac{1}{3}\\\dfrac{{-1}}{{12}}:x-\dfrac{5}{4}=-\dfrac{4}{3}\\\dfrac{{-1}}{{12}}:x=-\dfrac{4}{3}+\dfrac{5}{4}\\\dfrac{{-1}}{{12}}:x=-\dfrac{{16}}{{12}}+\dfrac{{15}}{{12}}\\\dfrac{{-1}}{{12}}:x=\dfrac{{-1}}{{12}}\\x=\dfrac{{-1}}{{12}}:\dfrac{{-1}}{{12}}\\x=1\end{array}.
Vậy x_0=1.
Ta có
A = \dfrac{{ - 5}}{6}.\dfrac{{12}}{{ - 7}}.\left( {\dfrac{{ - 21}}{{15}}} \right) = \dfrac{{\left( { - 5} \right).12.\left( { - 21} \right)}}{{6.\left( { - 7} \right).15}} = \dfrac{{\left( { - 5} \right).2.6.\left( { - 7} \right).3}}{{6.\left( { - 7} \right).5.3}} = - 2
B = \dfrac{1}{6}.\dfrac{9}{{ - 8}}.\left( {\dfrac{{ - 12}}{{11}}} \right) = \dfrac{{9.\left( { - 12} \right)}}{{6.\left( { - 8} \right).11}} = \dfrac{9}{{44}}
Do đó
A+B=\left({-2}\right)+\dfrac{9}{{44}}=\left({\dfrac{{-88}}{{44}}}\right)+\dfrac{9}{{44}}=\dfrac{{-79}}{{44}}.
Điền cụm từ thích hợp vào chỗ trống: “Muốn nhân hai phân số với nhau thì ta …"
Muốn nhân hai phân số, ta nhân các tử với nhau và nhân các mẫu với nhau.
A = \dfrac{4}{5}.\dfrac{{20}}{8}.\left( { - \dfrac{4}{3}} \right) = \dfrac{{4.20.( - 4)}}{{5.8.3}} = \dfrac{{4.5.2.2.( - 4)}}{{5.2.4.3}} = \dfrac{{2.( - 4)}}{3} = \dfrac{{ - 8}}{3}
B = \dfrac{{ - 2}}{{11}}.\dfrac{5}{{18}}.\left( {\dfrac{{ - 121}}{{25}}} \right) = \dfrac{{ - 2.5.( - 121)}}{{11.18.25}} = \dfrac{{ - 2.5.11.( - 11)}}{{11.2.9.5.5}} = \dfrac{{( - 1).( - 11)}}{{9.5}} = \dfrac{{11}}{{45}}
Do đó:
A+B=-\dfrac{8}{3}+\dfrac{{11}}{{45}}=-\dfrac{{120}}{{45}}+\dfrac{{11}}{{45}}=\dfrac{{-109}}{{45}}.
Kết quả của phép tính \frac{7}{4}.\left( { - \frac{2}{5}} \right) là:
Ta có: \dfrac{7}{4}.\left( { - \dfrac{2}{5}} \right) = \dfrac{7}{4}.\dfrac{{ - 2}}{5} = \dfrac{{7.( - 2)}}{{4.5}} = \dfrac{{7.( - 2)}}{{2.2.5}} = \dfrac{{7.( - 1)}}{{1.2.5}} = \dfrac{{ - 7}}{{10}}.
Thực hiện phép tính \dfrac{{ - 7}}{3}:\dfrac{{14}}{9} ta được kết quả là:
Ta có: \dfrac{{ - 7}}{3}:\dfrac{{14}}{9} = \dfrac{{ - 7}}{3}.\dfrac{9}{{14}} = \dfrac{{ - 7.9}}{{3.14}} = \dfrac{{ - 7.3.3}}{{3.2.7}} = \dfrac{{ - 3}}{2}.
Kết quả của phép tính 0,7.\dfrac{4}{5} là:
Ta có: 0,7.\dfrac{4}{5} = \dfrac{7}{{10}}.\dfrac{4}{5} = \dfrac{{7.4}}{{10.5}} = \dfrac{{7.2.2}}{{2.5.5}} = \dfrac{{7.2}}{{5.5}} = \dfrac{{14}}{{25}} > 0.
Số nào sau đây là kết quả của phép tính - 2:\left( {1\dfrac{1}{6}} \right).
Ta có: - 2:\left( {1\dfrac{1}{6}} \right) = - 2:\dfrac{7}{6} = - 2.\dfrac{6}{7} = \dfrac{{ - 2.6}}{7} = \dfrac{{ - 12}}{7}.
2\dfrac{1}{3}:\left({-\dfrac{6}{5}}\right)=\dfrac{7}{3}:\left({\dfrac{{-6}}{5}}\right)=\dfrac{7}{3}.\left({\dfrac{{-5}}{6}}\right)=\dfrac{{-35}}{{18}}.
Cho A = \dfrac{4}{5}.\dfrac{{20}}{8}.\left( { - \dfrac{4}{3}} \right);\,B = \dfrac{{ - 2}}{{11}}.\dfrac{5}{{18}}.\left( {\dfrac{{ - 121}}{{25}}} \right). So sánh A và B.
A = \dfrac{4}{5}.\dfrac{{20}}{8}.\left( { - \dfrac{4}{3}} \right) = \dfrac{{4.20.( - 4)}}{{5.8.3}} = \dfrac{{4.5.2.2.( - 4)}}{{5.2.4.3}} = \dfrac{{2.( - 4)}}{3} = \dfrac{{ - 8}}{3}
B = \dfrac{{ - 2}}{{11}}.\dfrac{5}{{18}}.\left( {\dfrac{{ - 121}}{{25}}} \right) = \dfrac{{ - 2.5.( - 121)}}{{11.18.25}} = \dfrac{{ - 2.5.11.( - 11)}}{{11.2.9.5.5}} = \dfrac{{( - 1).( - 11)}}{{9.5}} = \dfrac{{11}}{{45}}
Ta có: \dfrac{{ - 8}}{3} < 0 (vì tử và mẫu khác dấu);
\dfrac{{11}}{{45}} > 0 (vì tử và mẫu cùng dấu)
Do đó \dfrac{{ - 8}}{3} < \dfrac{{11}}{{45}} hay A < B.
Tìm x biết \dfrac{5}{{11}}x = \dfrac{{25}}{{44}}.
Ta có: \dfrac{5}{{11}}x = \dfrac{{25}}{{44}}
x = \dfrac{{25}}{{44}}:\dfrac{5}{{11}}
x = \dfrac{{25}}{{44}}.\dfrac{{11}}{5}
x = \dfrac{{25.11}}{{44.5}}
x = \dfrac{{5.5.11}}{{4.11.5}}
x = \dfrac{5}{4}
Vậy x = \dfrac{5}{4}.
Tìm số x thoả mãn: x:\left( {\dfrac{2}{9} - \dfrac{1}{5}} \right) = \dfrac{8}{{16}}.
Ta có: x:\left( {\dfrac{2}{9} - \dfrac{1}{5}} \right) = \dfrac{8}{{16}}
x:\left( {\dfrac{{10}}{{45}} - \dfrac{9}{{45}}} \right) = \dfrac{1}{2}
x:\dfrac{1}{{45}} = \dfrac{1}{2}
x = \dfrac{1}{2}.\dfrac{1}{{45}}
x = \dfrac{{1.1}}{{2.45}}
x = \dfrac{1}{{90}}
Vậy x = \dfrac{1}{{90}}.
Gọi {x_0} là giá trị thỏa mãn \left( {\dfrac{6}{7} - \dfrac{3}{5}} \right):\dfrac{{2x}}{3} = - \dfrac{{11}}{{18}}. Chọn câu đúng.
Ta có:
\left( {\dfrac{6}{7} - \dfrac{3}{5}} \right):\dfrac{{2x}}{3} = - \dfrac{{11}}{{18}}
\left( {\dfrac{{30}}{{35}} - \dfrac{{21}}{{35}}} \right):\dfrac{{2x}}{3} = - \dfrac{{11}}{{18}}
\dfrac{9}{{35}}:\dfrac{{2x}}{3} = - \dfrac{{11}}{{18}}
\dfrac{{2x}}{3} = \dfrac{9}{{35}}:\left( { - \dfrac{{11}}{{18}}} \right)
\dfrac{{2x}}{3} = \dfrac{9}{{35}}.\dfrac{{ - 18}}{{11}}
\dfrac{{2x}}{3} = \dfrac{{9.( - 18)}}{{35.11}}
\dfrac{2}{3}.x = \dfrac{{ - 162}}{{385}}
x = \dfrac{{ - 162}}{{385}}:\dfrac{2}{3}
x = \dfrac{{ - 162}}{{385}}.\dfrac{3}{2}
x = \dfrac{{ - 162.3}}{{385.2}}
x = \dfrac{{ - 81.2.3}}{{385.2}}
x = \dfrac{{ - 243}}{{385}}
Vậy {x_0} = \dfrac{{ - 243}}{{385}} < \dfrac{{385}}{{385}} = 1.