Đề kiểm tra 15 phút chương 1: Hàm số lượng giác và phương trình lượng giác - Đề số 2

\(x = \dfrac{\pi }{3} + k\pi \).

\(x = \dfrac{\pi }{2} + k2\pi \).

\(x =- \dfrac{\pi }{3} + k\pi \).

\(x = \dfrac{\pi }{2} + k2\pi \left( {k \in Z} \right)\)

\(x = k2\pi \left( {k \in Z} \right)\)

\(x = \dfrac{\pi }{2} + k\pi \left( {k \in Z} \right)\)

\(\cos x \ne 1 \Leftrightarrow x \ne \dfrac{\pi }{2} + k\pi \left( {k \in Z} \right)\)

\(\cos x \ne  - 1 \Leftrightarrow x \ne  - \dfrac{\pi }{2} + k2\pi \left( {k \in Z} \right)\)    

\(\cos x \ne 0 \Leftrightarrow x \ne \dfrac{\pi }{2} + k2\pi \left( {k \in Z} \right)\)

$x =  \pm \dfrac{\pi }{3} + k2\pi $.

$x =  \pm \dfrac{\pi }{6} + k2\pi $.

$x =  \pm \dfrac{\pi }{6} + k\pi $.

\(y = \cos x\)

\(y = \cot x\)

\(y = \tan x - 1\)

\({T_0} = 2\pi \)

\({T_0} = \pi \)

\({T_0} = 4{\pi ^2}\)

$x =  - \dfrac{\pi }{2} + k2\pi $.

$x = \dfrac{\pi }{2} + k\pi $.

$x = k\pi $.

\(\min y = \dfrac{4}{3};\max y = 3\)

\(\min y = \dfrac{4}{3};\max y = 2\)

\(\min y = \dfrac{1}{2};\max y = 2\)

\(D = \mathbb{R}\backslash \left\{ {\dfrac{\pi }{4} + k\dfrac{\pi }{3},\dfrac{{n\pi }}{5};k,n \in \mathbb{Z}} \right\}\)

\(D = \mathbb{R}\backslash \left\{ {\dfrac{\pi }{5} + k\dfrac{\pi }{3},\dfrac{{n\pi }}{5};k,n \in \mathbb{Z}} \right\}\)

\(D = \mathbb{R}\backslash \left\{ {\dfrac{\pi }{6} + k\dfrac{\pi }{4},\dfrac{{n\pi }}{5};k,n \in \mathbb{Z}} \right\}\)

\(\max y = 1,\min y = 1 - \sqrt 3 \)

\(\max y = 3,\min y = 1 - \sqrt 3 \)

\(\max y = 2,\min y = 1 - \sqrt 3 \)

\(x = \dfrac{\pi }{6} + k\pi \).

\(x = k\pi \).

\(x = \dfrac{\pi }{4} + k\pi \).

\(R\backslash \left\{ {\dfrac{\pi }{2} + k\pi ,k \in Z} \right\}\)

\(R\backslash \left\{ {k\pi ,k \in Z} \right\}\)

\(R\)