Biết rằng \(\int\limits_{}^{} {{e^x}\cos xdx}  = \left( {a\cos x + b\sin x} \right){e^x} + C\,\,\left( {a;b \in R} \right)\). Tính tổng \(T = a + b\).

\(\dfrac{{250}}{3}\;{\rm{m}}\).

\(270\;{\rm{m}}\).

\(200\;{\rm{m}}\).

\(\dfrac{{110}}{3}\;{\rm{m}}\).

\(S = \dfrac{{20}}{3}\)

\(S = \dfrac{{496}}{{15}}\)

\(S = \dfrac{4}{3}\)   

\(S = \dfrac{5}{3}\)

\(\int\limits_a^b {f\left( x \right)dx}  + \int\limits_b^c {f\left( x \right)dx}  = \int\limits_a^c {f\left( x \right)dx} \)                        

\(\int\limits_a^b {\left[ {f\left( x \right) + g\left( x \right)} \right]dx}  = \int\limits_a^b {f\left( x \right)dx}  + \int\limits_a^b {g\left( x \right)dx} \)

\(\int\limits_a^b {f\left( {k.x} \right)dx}  = k\int\limits_a^b {f\left( x \right)dx} \)                         

\(\int\limits_a^b {k.f\left( x \right)dx}  = k.\int\limits_a^b {f\left( x \right)dx} \)

\(\int\limits_{}^{} {f\left( x \right)dx}  = \dfrac{{{2^x}}}{{\ln 2}} + \sin x + x + C\)

\(\int\limits_{}^{} {f\left( x \right)dx}  = \dfrac{{{2^x}}}{{\ln 2}} - \sin x + x + C\)

\(\int\limits_{}^{} {f\left( x \right)dx}  = {2^x}.\ln 2 + \sin x + x + C\)      

\(\int\limits_{}^{} {f\left( x \right)dx}  = {2^x}.\ln 2 - \sin x + x + C\)

\(S = 8\)

\(S = \dfrac{{220}}{3}\)

\(S = \dfrac{{76}}{3}\)

\(S = \dfrac{{148}}{3}\)

\(P = 11\)

\(P = 5\)

\(P = 2\)

\(P =  - 2\)