Cho biểu thức $P = \left( {\dfrac{{4\sqrt x }}{{2 + \sqrt x }} + \dfrac{{8x}}{{4 - x}}} \right):\left( {\dfrac{{\sqrt x  - 1}}{{x - 2\sqrt x }} - \dfrac{2}{{\sqrt x }}} \right)$

Tìm $m$ để với mọi giá trị  $x > 9$ ta có: $m\left( {\sqrt x  - 3} \right)P > x + 1$

$P = \sqrt 3  - 1$

$P = \sqrt 3  + 1$

$P = 2\sqrt 3$

$P = \sqrt 3  + 2$

$A = \dfrac{1}{2}$

$A = 2\sqrt x  + \dfrac{1}{2}$

$A = \dfrac{1}{2}$ hoặc $A = 2\sqrt x  - \dfrac{1}{2}$

$A = 2\sqrt x  - \dfrac{1}{2}$

$B > 2$

$B > 1$

$B = 1$

$B < 2$

$Q = \dfrac{{\sqrt x }}{{\sqrt {x + y} }}$                     

$Q = \dfrac{{\sqrt {x + y} }}{{\sqrt {x - y} }}$

$Q = \dfrac{{\sqrt {x - y} }}{{\sqrt {x + y} }}$                     

$Q = \dfrac{{\sqrt y }}{{\sqrt {x + y} }}$

$Q = 2$                             

$Q = \sqrt 2$

$Q = \dfrac{1}{2}$

$Q = \dfrac{{\sqrt 2 }}{2}$

$Q = \dfrac{{\sqrt x }}{{\sqrt {x + y} }}$                     

$Q = \dfrac{{\sqrt {x + y} }}{{\sqrt {x - y} }}$

$Q = \dfrac{{\sqrt {x - y} }}{{\sqrt {x + y} }}$                     

$Q = \dfrac{{\sqrt y }}{{\sqrt {x + y} }}$

$Q = \dfrac{{\sqrt x }}{{\sqrt {x + y} }}$                     

$Q = \dfrac{{\sqrt {x + y} }}{{\sqrt {x - y} }}$

$Q = \dfrac{{\sqrt {x - y} }}{{\sqrt {x + y} }}$                     

$Q = \dfrac{{\sqrt y }}{{\sqrt {x + y} }}$