Viết biểu thức \(\left( {3x - 4} \right)\left( {9{x^2} + 12x + 16} \right)\) dưới dạng hiệu hai lập phương

\({x^3} - 3xy + 3{x^2}y + {y^3}\)

\({x^3} - 6{x^2}y + 12x{y^2} - 8{y^3}\)

\({x^3} - 6{x^2}y + 12x{y^2} - 4{y^3}\)

\({x^3} - 3{x^2}y + 12x{y^2} - 8{y^3}\)

\({\left( {2x + 9} \right)^3}\).

\({\left( {2x + 3} \right)^3}\).

\({\left( {4x + 3} \right)^3}\).

\({\left( {4x + 9} \right)^3}\).

\({\left( {2x - y} \right)^3}\).

\({\left( {x - 2y} \right)^3}\).

\({\left( {4x - y} \right)^3}\).

\({\left( {2x + y} \right)^3}\).

\({y^3} + {6^3}\).

\({\left( {\dfrac{y}{2}} \right)^3} + {6^3}\).

\({\left( {\dfrac{y}{2}} \right)^3} + {36^3}\).

\({\left( {\dfrac{y}{4}} \right)^3} + {6^3}\).

\(x =  - 4\).

\(x = 4\).

\(x =  - 8\).

\(x = 8\).

\(x =  - 3\).

\(x =  - \dfrac{1}{3}\).

\(x = 3\).

\(x = \dfrac{1}{3}\).