Biết rằng hệ phương trình $\left\{ \begin{array}{l}\sqrt {{x^2} + {y^2}}  + \sqrt {2xy}  = 8\sqrt 2 \\\sqrt x  + \sqrt y  = 4\end{array} \right.$ có nghiệm duy nhất $\left( {x;y} \right)$ . Tính $\dfrac{x}{y}$ .

$m = \dfrac{7}{5}$                             

$m = \dfrac{4}{5}$   

$m = \dfrac{5}{7}$   

$m = \dfrac{1}{5}$

$m > \dfrac{4}{5}$                             

$m < \dfrac{4}{5}$

$m > \dfrac{5}{4}$

$m < \dfrac{5}{4}$

$m > \dfrac{4}{5}$                             

$m < \dfrac{4}{5}$

$m > \dfrac{5}{4}$

$m < \dfrac{5}{4}$

$m = 1$                             

$m = 0$  

$m = 2$         

$m =  - 1$

$y =  - x - 2$                              

$y = x + 2$    

$y = x - 2$

$y = 2 - x$

$m \in \left\{ { - 3; - 2} \right\}$                             

$m \in \left\{ { - 3; - 2;0;1} \right\}$

$m \in \left\{ { - 3; - 2;0} \right\}$

$m =  - 3$

$m \in \left\{ { - 3; - 2} \right\}$                             

$m \in \left\{ { - 3; - 2;0;1} \right\}$

$m \in \left\{ { - 3; - 2;0} \right\}$

$m =  - 3$