\(\sqrt {{{\rm{x}}^2}}  = 5\) thì \(x\) bằng:

\((x - 2)(x + 2)(x + 1)\)

\((x - 4)(x + 4)(x + 1)\)

\((x - 2)(x + 2)(x - 1)\)

\(({x^2} + 4)(x + 1)\)

\(236400\) đồng

\(239400\) đồng

\(240400\) đồng

\(239600\) đồng

\(24\) quyển 

\(20\) quyển

\(4\) quyển 

\(22\) quyển

\(24\) quyển 

\(20\) quyển

\(4\) quyển 

\(22\) quyển

\({120^0}\)

\({30^0}\)

\({45^0}\)

\({60^0}\)

\(\Delta BEK \backsim \Delta CEA\)

\(\Delta BEK \backsim \Delta CBE\)

\(\Delta BEK \backsim \Delta CEB\)

\(\Delta BEK \backsim \Delta ECB\)

\(BE = 2\sqrt 2 \,cm;\dfrac{{BE}}{{EK}} = 2;\dfrac{{CE}}{{EB}} = 2\)

\(BE = 2\sqrt 2 \,cm;\dfrac{{BE}}{{EK}} = 2\sqrt 2 ;\dfrac{{CE}}{{EB}} = \dfrac{{\sqrt 2 }}{2}\)

\(BE = 2\sqrt 2 \,cm;\dfrac{{BE}}{{EK}} = \sqrt 2 ;\dfrac{{CE}}{{EB}} = \sqrt 2 \)      

\(BE = \sqrt 2 \,cm;\dfrac{{BE}}{{EK}} = \sqrt 2 ;\dfrac{{CE}}{{EB}} = \sqrt 2 \)