Tìm số nghiệm nguyên của bất phương trình ${\left( {\dfrac{1}{5}} \right)^{{x^2} - 2x}} \ge \dfrac{1}{{125}}$

$R$

$\left( { - \infty ;1} \right)$

$\left( {1; + \infty } \right)$ 

$\emptyset$

$\left( {2;3} \right)$                                   

$\left( {1;2} \right)$                            

$\left\{ 3 \right\}$                        

$\left\{ {\dfrac{1}{3}} \right\}$

$x <  - \ln 2$ hoặc $x > \ln 2$           

$- \ln 2 < x < \ln 2$

$x < \dfrac{1}{2}$ hoặc $x > 2$     

$\dfrac{1}{2} < x < 2$

$\left[ {1; + \infty } \right)$

$( - \infty ;1]$

$\left( { - \infty ;\dfrac{{10}}{3}} \right)$

$\left( {\dfrac{{10}}{3}; + \infty } \right)$  

$\left( { - \infty ; - 1} \right]$.

$\left[ { - 1; + \infty } \right)$.

$\left( { - \infty ; - 1} \right)$.

$\left( { - 1; + \infty } \right)$.

$(0, + \infty )$

$( - \infty , + \infty )$

$(2, + \infty )$           

$( - \infty ,0)$

$\left( { - 1; + \infty } \right)$

$\left( { - \infty ; - 1} \right)$

$\left( {2; + \infty } \right)$

$\left( { - \infty ; - 2} \right)$