Tìm nguyên hàm của hàm số \(f\left( x \right)=3\cos x+\dfrac{1}{{{x}^{2}}}\) trên \(\left( 0;\,+\infty \right)\).

\( - \overrightarrow a \) hoặc \( - \overrightarrow b \)

\(\left[ {\overrightarrow a ,\overrightarrow b } \right]\)    

\(\overrightarrow a  - \overrightarrow b \)

\(\overrightarrow a  + \overrightarrow b \)

\({{e}^{-2}}\)                          

\({{e}^{3}}-e\)             

\(e-{{e}^{3}}\)                         

\(\left| {{z_1}} \right| + \left| {{z_2}} \right| = 4\).

\(\left| {{z_1}} \right| + \left| {{z_2}} \right| = 2\sqrt 5 \).

\(\left| {{z_1}} \right| + \left| {{z_2}} \right| = 10\).

\(\left| {{z_1}} \right| + \left| {{z_2}} \right| = \sqrt 5 \).

\(\int {0dx}  = C\)       

\(\int {dx}  = C\)         

\(\int {dx}  = 0\)          

\(\int {0dx}  = x + C\)

\({(x + 1)^2} + {(y + 2)^2} + {(z - 3)^2} = 53.\)

\({(x + 1)^2} + {(y + 2)^2} + {(z + 3)^2} = 53.\)

\({(x - 1)^2} + {(y - 2)^2} + {(z - 3)^2} = 53.\)

\({(x - 1)^2} + {(y - 2)^2} + {(z + 3)^2} = 53.\)