Số các cặp số nguyên \(\left( {x;y} \right)\) thỏa mãn \(\dfrac{1}{{18}} < \dfrac{x}{{12}} < \dfrac{y}{9} < \dfrac{1}{4}\) là:

$ > $  

$ < $  

$ = $  

Tất cả các đáp án trên đều sai

$180$ 

\(500\)  

\(750\) 

\(450\)

\({3^3}{.7^2}\)                     

\({3^3}{.7^3}.11.19\)             

\({3^2}{.7^2}.11.19\)

\({3^3}{.7^2}.11.19\)

\(\dfrac{2}{{ - 3}} > \,\,\dfrac{{ - 7}}{8}\)     

\(\dfrac{{ - 22}}{{33}} = \dfrac{{200}}{{ - 300}}\)

\( - \dfrac{2}{5} < \dfrac{{196}}{{294}}\)

\(\dfrac{{ - 3}}{5} < \,\,\dfrac{{39}}{{ - 65}}\)

\(\dfrac{{ - 156}}{{149}};\dfrac{{ - 3}}{4};\dfrac{1}{{12}}\) 

\(\dfrac{1}{{12}};\dfrac{{ - 156}}{{149}};\dfrac{{ - 3}}{4}\)

\(\dfrac{{ - 3}}{4};\dfrac{{ - 156}}{{149}};\dfrac{1}{{12}}\)

\(\dfrac{1}{{12}};\dfrac{{ - 3}}{4};\dfrac{{ - 156}}{{149}}\)

$\dfrac{{ - 21}}{{91}},\dfrac{{26}}{{91}}$ 

$\dfrac{{ - 3}}{{13}},\dfrac{2}{7}$  

$\dfrac{{21}}{{91}},\dfrac{{26}}{{91}}$

$\dfrac{{ - 21}}{{91}},\dfrac{{36}}{{91}}$

\(\dfrac{{ - 1}}{7}\) 

\(\dfrac{{ - 1}}{{14}}\)  

\(\dfrac{4}{{ - 56}}\)         

\(\dfrac{{ - 1}}{{70}}\)