Giá trị của $x$ thỏa mãn ${\log _{\frac{1}{2}}}(3 - x) = 2$ là

$\left\{ {\dfrac{{1 + \sqrt 2 }}{2}} \right\}$

$\left\{ {2;41} \right\}$

$\left\{ {1 - \sqrt 2 ;1 + \sqrt 2 } \right\}$     

$\left\{ {1 + \sqrt 2 } \right\}$ 

$x = 1$          

$x = \sqrt[8]{{{3^5}}} - 2$    

$x = \sqrt[4]{{{3^5}}} - 2$

$x = \sqrt[4]{3} - 2.$

$x = 15$

$x = \dfrac{1}{5}$

$x = 25$

$x = 5$

$x = 63$

$x = 65$

$x = 82$ 

$x = 80$

$S = \left\{ { - 3;3} \right\}$.

$S = \left\{ {\sqrt {10} } \right\}$.

$S = \left\{ 3 \right\}$.

$S = \left\{ { - \sqrt {10} ;\sqrt {10} } \right\}$.

$\dfrac{{ - 1 + \sqrt 5 }}{2}.$

$\dfrac{{ - 1 - \sqrt 5 }}{2}.$

$\dfrac{{1 + \sqrt 5 }}{2}.$

$\dfrac{1}{2}.$