Giá trị biểu thức $P = \dfrac{{{{125}^6}.\left( { - {{16}^3}} \right)2.\left( { - {2^3}} \right)}}{{{{25}^3}.{{\left( { - {5^2}} \right)}^4}}}$ là:

$a > 0$ 

 $a = 0$ 

$a \ne 0$       

$a < 0$ 

$a < 0$            

$a > 0$            

$a \in R$         

$a \in Z$ 

 $P = {a^{\frac{1}{2}}}$      

$P = {a^{\frac{9}{2}}}$       

$P = {a^{\frac{{11}}{6}}}$

$P = {a^3}$

${a^{\frac{m}{n}}} = \sqrt[n]{{{a^m}}}$ 

${a^{\frac{m}{n}}} = \sqrt[m]{{{a^n}}}$ 

${a^{\frac{m}{n}}} = \sqrt[{mn}]{a}$      

${a^{\frac{m}{n}}} = \sqrt[m]{{{a^{mn}}}}$ 

${a^n}$ 

${b^n}$          

${a^\alpha }$ 

${b^\alpha }$ 

$P = {2^{\frac{{181}}{{90}}}}$      

$P = {2^{\frac{{181}}{9}}}$

$P = {2^{\frac{5}{6}}}$      

$P = {2^{\frac{5}{3}}}$

${a^{\frac{1}{n}}} = \sqrt[n]{a}$ 

${a^{\frac{1}{n}}} = \sqrt {{a^n}}$         

${a^{\frac{1}{n}}} = {a^n}$ 

 ${a^{\frac{1}{n}}} = \sqrt[a]{n}$