Cho \(\Delta ABC = \Delta DEF.\) Biết rằng \(AB = 6cm,\) \(AC = 8cm\) và \(EF = 10cm.\) Chu vi tam giác \(DEF\) là

\(\widehat A = \widehat D = {105^0};\,\widehat C\, = \widehat F = {40^0}.\)

\(\widehat A = \widehat D = {90^0};\,\widehat C\, = \widehat F = {50^0}.\)

\(\widehat A = \widehat D = {95^0};\,\widehat C\, = \widehat F = {40^0}.\)

\(\widehat A = \widehat D = {40^0};\,\widehat C\, = \widehat F = {95^0}.\)

\(4\,cm\)

\(6\,cm\)

\(8\,cm\)

\(10\,cm\)

\(\widehat A < \widehat C < \widehat B\)

\(\widehat A > \widehat B = \widehat C\)

\(\widehat A > \widehat B > \widehat C\)

\(\widehat A > \widehat C > \widehat B\)

\(PQ = DE\)

\(PR = EF\)

\(\widehat Q = \widehat E\)

\(\widehat D = \widehat P\)

\(\widehat C = {45^0}\)

\(\widehat B = {45^0}\)

\(\widehat A = {45^0}\)

\(\widehat C = {90^0}\)

\(\Delta MNP = \Delta IJK\)

\(\Delta MNP = \Delta IKJ\)

\(\Delta MNP = \Delta KIJ\)

\(\Delta MNP = \Delta JKI\)

\(\widehat D = {80^0};\,\widehat K = {40^0}\)

\(\widehat D = {40^0};\,\widehat K = {60^0}\)

\(\widehat D = {60^0};\,\widehat K = {80^0}\)

\(\widehat D = {40^0};\,\widehat K = {80^0}\)