so sánh 2 phân số A=2021^2021+1/2021^2022+1 và B=2021^2020+1/2021^2021+1

2 câu trả lời

Ta có `:`

`A = ( 2021^2021 + 1 )/( 2021^2022 + 1 )`

`2021 . A = ( 2021^2022 + 2021 )/( 2021^2022 + 1 )`

`2021 . A = ( 2021^2022 + 1 + 2020 )/( 2021^2022 + 1 )`

`2021 . A = 1 + 2020/( 2021^2022 + 1 )`

Lại có `:`

`B = ( 2021^2020 + 1 )/( 2021^2021 + 1 )`

`2021 . B = ( 2021^2021 + 2021 )/( 2021^2021 + 1 )`

`2021 . B = ( 2021^2021 + 1 + 2020 )/( 2021^2021 + 1 )`

`2021 . B = 1 + 2020/( 2021^2021 + 1 )`

Vì `2020/( 2021^2021 + 1 ) > 2020/( 2021^2022 + 1 )`

Nên `1 + 2020/( 2021^2021 + 1 ) > 1 + 2020/( 2021^2022 + 1 )`

Vậy `B>A`

Ta có `: A = ( 2021^2021 + 1 )/( 2021^2022 + 1 )`

`2021 . A = ( 2021^2022 + 2021 )/( 2021^2022 + 1 )`

`2021 . A = ( 2021^2022 + 1 + 2020 )/( 2021^2022 + 1 )`

`2021 . A = 1 + 2020/( 2021^2022 + 1 )`

Lại có `: B = ( 2021^2020 + 1 )/( 2021^2021 + 1 )`

`2021 . B = ( 2021^2021 + 2021 )/( 2021^2021 + 1 )`

`2021 . B = ( 2021^2021 + 1 + 2020 )/( 2021^2021 + 1 )`

`2021 . B = 1 + 2020/( 2021^2021 + 1 )`

Vì `2020/( 2021^2021 + 1 ) > 2020/( 2021^2022 + 1 )` nên `1 + 2020/( 2021^2021 + 1 ) > 1 + 2020/( 2021^2022 + 1 )`

`⇒ 2021 . B > 2021 . A ⇒ B > A`

Vậy `, B > A .`

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