Tính $x$ trong hình vẽ sau:

$10\,\,\left( {cm} \right)$

$12\,\,\left( {cm} \right)$     

$11\,\,\left( {cm} \right)$     

$13\,\left( {cm} \right)$

$\sqrt {10} \,\,\left( {cm} \right)$

$\sqrt {13} \,\,\left( {cm} \right)$

$\sqrt {12} \,\,\left( {cm} \right)$

$12\,\left( {cm} \right)$

$\sqrt {10} \,\,\left( {cm} \right)$

$\sqrt {13} \,\,\left( {cm} \right)$

$\sqrt {12} \,\,\left( {cm} \right)$

$12\,\left( {cm} \right)$

$M{N^2} = M{P^2} - N{P^2}$

$M{P^2} = M{N^2} + N{P^2}$

$N{P^2} = M{N^2} + M{P^2}$      

$M{N^2} = M{P^2} + N{P^2}$

$BC = 6\,dm$    

$BC = \sqrt {23} \,dm$

$BC = 4\,dm$

$BC = \sqrt {32} \,dm$

$9\,cm;\,12\,cm$    

$10\,cm;\,16\,cm.$

$12\,cm;\,16\,cm$

$12\,cm;\,14\,cm$

$AH = 4,8\,cm;\,AB = 6\,cm$

$AH = 8,4\,cm;\,AB = 6\,cm$

$AH = 4\,cm;\,AB = 6\,cm$

$AH = 5\,cm;\,AB = 6\,cm$