Tìm \(x\) biết \(\dfrac{2}{3} + \dfrac{5}{3}x = \dfrac{5}{7}\)

\(R = I \cup Q\)

\(I \subset R\)

\(I \cap Q = \emptyset \)

Cả A, B, C đều đúng

\(R\)

\(Q\)

\(\emptyset \)

\(I\)

\(1;2;...9\)

\(3\)

\(\emptyset \)

\(0;1\)

\(\dfrac{{ - 1}}{5} < \dfrac{{ - 1}}{4} < \dfrac{1}{3} < 0,5 < 2 < \sqrt 5 \)

\(\dfrac{{ - 1}}{4} < \dfrac{{ - 1}}{5} < 0,5 < \dfrac{1}{3} < 2 < \sqrt 5 \)

\(\dfrac{{ - 1}}{4} < \dfrac{{ - 1}}{5} < \dfrac{1}{3} < 0,5 < \sqrt 5  < 2\)

\(\dfrac{{ - 1}}{4} < \dfrac{{ - 1}}{5} < \dfrac{1}{3} < 0,5 < 2 < \sqrt 5 \)

\(121\) hoặc \( - 121\)

\(\sqrt {11} \) hoặc \( - \sqrt {11} \)

\(\dfrac{{11}}{2}\)

\(22\) hoặc \( - 22\)

\(\dfrac{3}{8}\)

\(\dfrac{8}{3}\)

\(\dfrac{{31}}{6}\)

\(\dfrac{7}{2}\)

\(\dfrac{{2021}}{{2020}}\)

\(\dfrac{{2273}}{{1010}}\)

\(\dfrac{{2237}}{{1010}}\)

\(\dfrac{{4645}}{{2020}}\)