Giải bất phương trình \( - 2{x^2} + 3x - 7 \ge 0.\)

\(\left( { - \infty ; - 1} \right] \cup \left[ {7; + \infty } \right)\).

\(\left[ { - 1;7} \right]\).

\(\left( { - \infty ; - 7} \right] \cup \left[ {1; + \infty } \right)\).

\(\left[ { - 7;1} \right]\).

$S = \mathbb{R}.$

$S = \left( { - \infty ;2} \right).$

$S = \left( { - \dfrac{5}{2}; + \infty } \right).$

$S = \left[ {\dfrac{{20}}{{23}}; + \infty } \right).$

\(\left( { - \infty ;0} \right].\)

\(\left[ {8; + \infty } \right).\)

\(\left( { - \infty ;1} \right].\)

\(\left[ {6; + \infty } \right).\)

\(x \in \left( { - \,\infty ;5} \right) \cup \left( {3; + \,\infty } \right).\)

\(x \in \left( {3; + \,\infty } \right).\)

\(x \in \left( { - \,5;3} \right).\)

\(x \in \left( { - \,\infty ; - \,5} \right] \cup \left[ {3; + \,\infty } \right).\)

\(5.\)

\(6.\)

\(21.\)

\(40.\)

$x \le 1.$

\(1 \le x \le 4.\)

\(x \in \left( { - \,\infty ;1} \right] \cup \left[ {4; + \infty } \right).\)

\(x \ge 4.\)