Chọn câu sai:

\(\begin{array}{l} + )\,16{x^4}\left( {x - y} \right) - x + y\\ = 16{x^4}\left( {x - y} \right) - \left( {x - y} \right)\\ = \left( {16{x^4} - 1} \right)\left( {x - y} \right)\\ = \left[ {{{\left( {2x} \right)}^4} - 1} \right]\left( {x - y} \right)\\ = \left[ {{{\left( {2x} \right)}^2} - 1} \right]\left[ {\left( {2{x^2}} \right) + 1} \right]\left( {x - y} \right)\\ = \left( {2x - 1} \right)\left( {2x + 1} \right)\left( {4{x^2} + 1} \right)\left( {x - y} \right).\end{array}\)

\(\begin{array}{l} + )\;16{x^3} - 54{y^3}\\ = 2\left( {8{x^3} - 27{y^3}} \right)\\ = 2\left[ {{{\left( {2x} \right)}^3} - {{\left( {3y} \right)}^3}} \right]\\ = 2\left( {2x - 3y} \right)\left[ {{{\left( {2x} \right)}^2} + 2x.3y + {{\left( {3y} \right)}^2}} \right]\\ = 2\left( {2x - 3y} \right)\left( {4{x^2} + 6xy + 9{y^2}} \right).\end{array}\)

Vậy A, B, D đúng. C sai