Cho hàm số \(y = f\left( x \right)\) thỏa mãn \(\mathop {\lim }\limits_{x \to x_0^ - } f\left( x \right) = L\). Khi đó ta có thể hiểu rằng:

\( - \infty \)

\(\dfrac{5}{2}\).

\( + \infty \)

$2$

7

3

\( - 7\)

\( - 3\)

3

\( - \infty \)

2

\( + \infty .\)

1

\( - \infty \).

0

\( + \infty \).

\(\mathop {\lim }\limits_{x \to {x_0}} x = {x_0}\)  

\(\mathop {\lim }\limits_{x \to {x_0}} x = 1\)

\(\mathop {\lim }\limits_{x \to {x_0}} c = {x_0}\)

\(\mathop {\lim }\limits_{x \to {x_0}} x = 0\)

\(\dfrac{1}{4}.\)

\(\dfrac{1}{2}.\)

\(\dfrac{1}{3}.\)

\(\dfrac{1}{5}.\)

\(\mathop {\lim }\limits_{x \to {x_0}} \dfrac{{f\left( x \right)}}{{g\left( x \right)}} = \dfrac{L}{M}\)

\(\mathop {\lim }\limits_{x \to {x_0}} \left[ {f\left( x \right).g\left( x \right)} \right] = L.M\)

\(\mathop {\lim }\limits_{x \to {x_0}} \left[ {f\left( x \right) - g\left( x \right)} \right] = L - M\)    

\(\mathop {\lim }\limits_{x \to {x_0}} \left[ {f\left( x \right) + g\left( x \right)} \right] = L + M\)