Tìm \(x \in Z\) biết \(\left( {x + 1} \right) + \left( {x + 2} \right) + ... + \left( {x + 99} \right) + \left( {x + 100} \right) = 0\).

\(A = \left\{ {1; - 1;2; - 2;4; - 4;8; - 8} \right\}\)                    

\(A = \left\{ {0; \pm 1; \pm 2 \pm 4 \pm 8} \right\}\)                  

\(A = \left\{ {1;2;4;8} \right\}\)                                                        

\(A = \left\{ {0;1;2;4;8} \right\}\)

\( - 192873\)

\(1\)

\(0\)

\(\left( { - 192873} \right).\left( { - 2345} \right).{\left( { - 4} \right)^5}\)

$a = 5$

$a = 13$

$a =  - 13$  

$a = 9$

$x$  chia $3$ dư $1$                        

\(x \, \vdots \, 3\)                     

$x$ chia $3$ dư $2$                  

không kết luận được tính chia hết cho $3$ của \(x\)

\(n \in \left\{ { \pm 1; \pm 2 \pm 4} \right\}\) 

\(n \in \left\{ { - 5; - 3; - 2;0;1;3} \right\}\)                                  

\(n \in \left\{ {0;1;3} \right\}\)                                     

\(n \in \left\{ { \pm 1; \pm 5} \right\}\)

\(4\)                               

\(5\)      

\(8\)

\(6\)

\(a = b\)                               

\(a =  - b\)                                  

\(a = 2b\)                                     

Cả A, B đều đúng