Tìm \(x\) sao cho \(x - \dfrac{{ - 7}}{{12}} = \dfrac{{17}}{{18}} - \dfrac{1}{9}\).

$\dfrac{1}{{10}}$ 

$\dfrac{4}{5}$           

\(\dfrac{2}{5}\)          

\(\dfrac{{ - 1}}{{10}}\)

$\dfrac{{ - 53}}{{35}}$ 

\(\dfrac{{51}}{{35}}\)  

\(\dfrac{{ - 3}}{{35}}\)                  

\(\dfrac{3}{{35}}\)

$\dfrac{{ - 4}}{{11}} + \dfrac{7}{{ - 11}} > 1$ 

$\dfrac{{ - 4}}{{11}} + \dfrac{7}{{ - 11}} < 0$  

$\dfrac{8}{{11}} + \dfrac{7}{{ - 11}} > 1$

$\dfrac{{ - 4}}{{11}} + \dfrac{{ - 7}}{{11}} >  - 1$

\(\dfrac{{12}}{{33}}\) 

\(\dfrac{{177}}{{260}}\)  

\(\dfrac{{187}}{{260}}\)

\(\dfrac{{177}}{{26}}\)

$ - \dfrac{5}{{16}}$ 

\(\dfrac{5}{{16}}\)     

\(\dfrac{{19}}{{16}}\)       

\( - \dfrac{{19}}{{16}}\)

$\dfrac{9}{5}$ 

\(\dfrac{{11}}{5}\)  

\(\dfrac{{ - 11}}{5}\)

\(\dfrac{{ - 1}}{5}\)

$A > 1$          

\(A = \dfrac{2}{{11}}\)          

\(A = 1\)                

\(A = 0\)