Giá trị của $\tan {45^0} + \cot {135^0}$ bằng bao nhiêu?

$\sin \left( {180^\circ  - \alpha } \right) =  - \cos \alpha .$

$\sin \left( {180^\circ  - \alpha } \right) =  - \sin \alpha .$

$\sin \left( {180^\circ  - \alpha } \right) = \sin \alpha .$

$\sin \left( {180^\circ  - \alpha } \right) = \cos \alpha .$

$\sin \alpha  =  - \cos \beta .$      

$\cos \alpha  = \sin \beta .$

$\tan \alpha  = \cot \beta .$

$\cot \alpha  = \tan \beta .$

$\sin 90^\circ  < \sin 150^\circ .$

$\sin 90^\circ 15' < \sin 90^\circ 30'.$

$\cos 90^\circ 30' > \cos 100^\circ .$

$\cos 150^\circ  > \cos 120^\circ .$

$1.$

$\sqrt 2 .$

$\sqrt 3 .$

$0.$

$P = \sqrt 3 .$

$P = \dfrac{{\sqrt 3 }}{2}.$

$P = 1.$

$P = 0.$

$S = 0.$        

$S = 1.$

$S = 2.$

$S = 4.$