Các giá trị $x$ thỏa mãn $\dfrac{3}{5} - \left| {x - \dfrac{1}{2}} \right| = 25\%$ là:

$\begin{array}{l}\dfrac{3}{5} - \left| {x - \dfrac{1}{2}} \right| = 25\% \\\dfrac{3}{5} - \left| {x - \dfrac{1}{2}} \right| = \dfrac{{25}}{{100}}\\\dfrac{3}{5} - \left| {x - \dfrac{1}{2}} \right| = \dfrac{1}{4}\\\left| {x - \dfrac{1}{2}} \right| = \dfrac{3}{5} - \dfrac{1}{4}\\\left| {x - \dfrac{1}{2}} \right| = \dfrac{{12}}{{20}} - \dfrac{5}{{20}}\\\left| {x - \dfrac{1}{2}} \right| = \dfrac{7}{{20}}\end{array}$

TH1:

 $\begin{array}{l}x - \dfrac{1}{2} = \dfrac{7}{{20}}\\x = \dfrac{7}{{20}} + \dfrac{1}{2}\\x = \dfrac{7}{{20}} + \dfrac{{10}}{{20}}\\x = \dfrac{{17}}{{20}}\end{array}$

TH2:

$\begin{array}{l}x - \dfrac{1}{2} = \dfrac{{ - 7}}{{20}}\\x = \dfrac{{ - 7}}{{20}} + \dfrac{1}{2}\\x = \dfrac{{ - 7}}{{20}} + \dfrac{{10}}{{20}}\\x = \dfrac{3}{{20}}\end{array}$

Vậy $x = \dfrac{{17}}{{20}}$ và $x = \dfrac{3}{{20}}$.