Xác định tọa độ vecto(c)=5vecto(a) -2vecto(b) biết vecto(a)=(3;-2) vecto(b)=(1;4)
1 câu trả lời
Ta có
$\vec{c} = 5\vec{a} - 2\vec{b}$
$= 5(3,-2) - 2(1,4)$
$= (15,-10) - (2,8)$
$= (15-2, -10-8) = (13,-18)$
Vậy $\vec{c} = (13,-18)$
Ta có
$\vec{c} = 5\vec{a} - 2\vec{b}$
$= 5(3,-2) - 2(1,4)$
$= (15,-10) - (2,8)$
$= (15-2, -10-8) = (13,-18)$
Vậy $\vec{c} = (13,-18)$
