1 câu trả lời
Đáp án:
$\begin{array}{l}
x\sqrt {2x - 5} = 4\left( {dkxd:x \ge \frac{5}{2}} \right)\\
\Rightarrow {x^2}\left( {2x - 5} \right) = 16\\
\Rightarrow 2{x^3} - 5{x^2} - 16 = 0\\
\Rightarrow x = 3,255
\end{array}$
Đáp án:
$\begin{array}{l}
x\sqrt {2x - 5} = 4\left( {dkxd:x \ge \frac{5}{2}} \right)\\
\Rightarrow {x^2}\left( {2x - 5} \right) = 16\\
\Rightarrow 2{x^3} - 5{x^2} - 16 = 0\\
\Rightarrow x = 3,255
\end{array}$
