$n_{N_{2}}$ = 3,36 : 22,4 = 0,15 (mol)
$n_{N_2}=\dfrac{V_{N_2(đktc)}}{22,4}=\dfrac{3,36}{22,4}=0,15(mol)$
cho a,b,c>0 c²=a³+b³=3ab+c CMR : 2a²b²+2b²c²+2c²a²=a⁴+b⁴+c⁴
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