2 câu trả lời
`2/x = x/8`
`=> x . x = 8 . 2`
`=> x^2 = 16`
`=> x^2 = 4^2`
`=> x = ±4`
Vậy `x = ±4`
`#dtkc`
$\dfrac{2}{x}=\dfrac{x}{8}$
$⇒ 2.8=x.x$
$⇒ 16=x^2$
$⇒ (±4)^2=x^2$
$⇒ x=±4$
Vậy $x=±4$
$#thanhmaii2008$
`2/x = x/8`
`=> x . x = 8 . 2`
`=> x^2 = 16`
`=> x^2 = 4^2`
`=> x = ±4`
Vậy `x = ±4`
`#dtkc`
$\dfrac{2}{x}=\dfrac{x}{8}$
$⇒ 2.8=x.x$
$⇒ 16=x^2$
$⇒ (±4)^2=x^2$
$⇒ x=±4$
Vậy $x=±4$
$#thanhmaii2008$