pttnt x^4+2022x^2+2021x+2022

2 câu trả lời

Đáp án:

`x^4+2022x^2+2021x+2022`

`=(x^4+x^3+x^2)+(2021x^2+2021x+2021)-(x^3-1)`

`=x^2.(x^2+x+1)+2021.(x^2+x+1)-(x-1).(x^2+x+1)`

`=(x^2+x+1).(x^2+2021-x+1)`

`=(x^2+x+1).(x^2-x+2022)`

$#dariana$

 

`x^4+2022x^2+2021x+2022`

`=x^4+x^3-x^3+2021x^2+x^2+2021x+2021+1`

`=x^4+x^3+x^2+2021x^2+2021x+2021-x^3+1`

`=(x^4+x^3+x^2)+(2021x^2+2021x+2021)-(x^3-1)`

`=x^2(x^2+x+1)+2021(x^2+x+1)-(x-1)(x^2+x+1)`

`=(x^2+x+1)(x^2+2021-x+1)`

`=(x^2+x+1)(x^2-x+2022)`

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