Mg+HNO3---->Mg (NO3)2+N2O+H20 CÂN BẰNG phương trình
2 câu trả lời
$Mg^0 \to Mg^{+2} + 2e$ (4x)
$2N^{+5}+ 8e \to 2N^{+1}$ (1x)
$4Mg+10HNO_3\to 4Mg(NO_3)_2+N_2O+5H_2O$
$Mg^0 \to Mg^{+2} + 2e$ (4x)
$2N^{+5}+ 8e \to 2N^{+1}$ (1x)
$4Mg+10HNO_3\to 4Mg(NO_3)_2+N_2O+5H_2O$