Tính giá trị biểu thức  $A = \left( {\dfrac{{11}}{4}.\dfrac{{ - 5}}{9} - \dfrac{4}{9}.\dfrac{{11}}{4}} \right).\dfrac{8}{{33}}$

\(\dfrac{{ - 1}}{{16}}\)

\( - 2\)  

\(\dfrac{{ - 15}}{{32}}\)

\(\dfrac{{ - 5}}{{32}}\)

$1$ 

\(3\)  

\(\dfrac{1}{{ - 3}}\)    

\(\dfrac{1}{3}\)

$\dfrac{1}{4}$ 

\(\dfrac{1}{2}\)          

\( - \dfrac{1}{2}\)                        

\(1\)

\({\left( {\dfrac{{ - 7}}{6}} \right)^2} = \dfrac{{ - 49}}{{36}}\) 

\({\left( {\dfrac{2}{3}} \right)^3} = \dfrac{8}{9}\)  

\({\left( {\dfrac{2}{{ - 3}}} \right)^3} = \dfrac{8}{{ - 27}}\)          

\({\left( {\dfrac{{ - 2}}{3}} \right)^4} = \dfrac{{ - 16}}{{81}}\)

$ - \dfrac{1}{{10}}$ 

\( - \dfrac{4}{9}\)  

\( - \dfrac{4}{3}\)                               

\( - 4\)

\(x \in \left\{ { - 3; - 2; - 1} \right\}\)           

\(x \in \left\{ { - 4; - 3; - 2; - 1} \right\}\)

\(x \in \left\{ { - 3; - 2} \right\}\)         

\(x \in \left\{ { - 3; - 2; - 1;0} \right\}\)

$8$ 

\(\dfrac{9}{5}\)  

\(\dfrac{3}{5}\)          

\(2\)