Tìm $x$ sao cho $x - \dfrac{{ - 7}}{{12}} = \dfrac{{17}}{{18}} - \dfrac{1}{9}$.

$\dfrac{{ - 2}}{3};\dfrac{3}{2}$                 

$\dfrac{{ - 12}}{{13}};\dfrac{{13}}{{ - 12}}$  

$\dfrac{1}{2}; - \dfrac{1}{2}$

$\dfrac{3}{4};\dfrac{{ - 4}}{3}$

$\dfrac{{ - 53}}{{35}}$ 

$\dfrac{{51}}{{35}}$  

$\dfrac{{ - 3}}{{35}}$                  

$\dfrac{3}{{35}}$

$\dfrac{3}{2} + \dfrac{2}{3} > 1$ 

$\dfrac{3}{2} + \dfrac{2}{3} = \dfrac{{13}}{6}$     

$\dfrac{3}{4} + \left( {\dfrac{{ - 4}}{{17}}} \right) = \dfrac{{35}}{{68}}$

$\dfrac{4}{{12}} + \dfrac{{21}}{{36}} = 1$

$\dfrac{9}{{14}}$ 

$\dfrac{1}{{14}}$  

$\dfrac{{11}}{{14}}$                 

$\dfrac{1}{2}$

$\dfrac{{12}}{{33}}$ 

$\dfrac{{177}}{{260}}$  

$\dfrac{{187}}{{260}}$

$\dfrac{{177}}{{26}}$

$\dfrac{4}{{13}} - \dfrac{1}{2} = \dfrac{5}{{26}}$                       

$\dfrac{1}{2} - \dfrac{1}{3} = \dfrac{5}{6}$  

$\dfrac{{17}}{{20}} - \dfrac{1}{5} = \dfrac{{13}}{{20}}$

$\dfrac{5}{{15}} - \dfrac{1}{3} = \dfrac{1}{5}$

$M = \dfrac{2}{7};N = \dfrac{1}{{41}}$     

$M = 0;N = \dfrac{1}{{41}}$

$M = \dfrac{{ - 16}}{7};N = \dfrac{{83}}{{41}}$

$M =  - \dfrac{2}{7};N = \dfrac{1}{{41}}$