Giá trị của giới hạn $\mathop {\lim }\limits_{x \to {0^ + }} \dfrac{{\sqrt {{x^2} + x}  - \sqrt x }}{{{x^2}}}$ là:

$- 1.$

$1.$

$+ \infty .$

$0.$

$\mathop {\lim }\limits_{x \to  + \infty } {x^n} =  - \infty$           

$\mathop {\lim }\limits_{x \to  \pm \infty } {x^n} =  + \infty$        

$\mathop {\lim }\limits_{x \to  - \infty } {x^n} =  - \infty$

$\mathop {\lim }\limits_{x \to  - \infty } {x^n} =  + \infty$ 

$+ \infty$     

$- \infty$

$\dfrac{2}{3}$

$1$

$- \dfrac{3}{2}.$

$- \dfrac{2}{3}.$

$0.$

$+ \infty .$

$\lim \left( {{u_n} - 2{v_n}} \right) = \dfrac{1}{3}$

$\lim \left( {2{u_n} - {v_n}} \right) = 4$

$\lim \left( {{u_n} - {v_n}} \right) = 1$

$\lim \left( {{u_n} + {v_n}} \right) = \dfrac{1}{3}$

$0.$    

$- \dfrac{1}{4}.$      

$\dfrac{3}{4}.$

$- \dfrac{3}{4}.$