Câu hỏi:
2 năm trước

Cho sơ đồ chuyển hóa : \(N{H_2} - CH - COON{H_4}\mathrel{\mathop{\kern0pt\longrightarrow}
\limits_{}^{{\rm{dd}}.NaOH,{t^0}}} X\mathrel{\mathop{\kern0pt\longrightarrow}
\limits_{}^{{H_2}S{O_4}}} Y\mathrel{\mathop{\kern0pt\longrightarrow}
\limits_{_{}}^{C{H_3}OH,{H_2}S{O_4},{t^0}}} Z\)

Biết X, Y, Z đều là các chất vô cơ Chất Z là :

Trả lời bởi giáo viên

Đáp án đúng: a

\(\eqalign{
& N{H_2} - CH - COON{H_4} + NaOH \to N{H_2} - CH - COONa + N{H_3} + {H_2}O \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,X \cr
& 2N{H_2} - CH - COONa + {H_2}S{O_4}\buildrel {{T^0}} \over
\longrightarrow 2N{H_3}HS{O_4} - C{H_2} - COOH + N{a_2}S{O_4} \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Y \cr
& N{H_3}HS{O_4} - C{H_2} - COOH + C{H_3}OH \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} N{H_3}HS{O_4} - C{H_2} - C{\rm{OOC}}{H_3} + {H_2}O \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Z \cr} \)

Câu hỏi khác