Cho phương trình ${\log _2}\left[ {{{\log }_{\dfrac{1}{8}}}\left( {{x^3}} \right) + {{\log }_2}x + x + 1} \right] = 3.$ Mệnh đề nào sau đây là đúng?

$0$

$1$

$3$

$4$

\(D = \left( { - \infty ;\dfrac{{ - 3 - \sqrt {17} }}{2}} \right] \cup \left[ {\dfrac{{ - 3 + \sqrt {17} }}{2}; + \infty } \right)\)

\(D = \left( { - \infty ; - 3} \right) \cup \left( {1; + \infty } \right)\)

\(D = \left( {\dfrac{{ - 3 - \sqrt {17} }}{2}; - 3} \right) \cup \left( {\dfrac{{ - 3 + \sqrt {17} }}{2};1} \right)\)            

\(D = \left[ {\dfrac{{ - 3 - \sqrt {17} }}{2}; - 3} \right) \cup \left[ {\dfrac{{ - 3 + \sqrt {17} }}{2};1} \right)\)

\(x = \sqrt[M]{{2017!}} - 1\)

\(x = \sqrt[M]{{2018!}}\)        

\(x = \sqrt[M]{{2016!}}\)       

\(x = \sqrt[M]{{2017!}}\)

\(1 - \sqrt 3  \le x \le 0\)           

\(2 \le x \le 1 + \sqrt 3 \)

\(1 - \sqrt 3  \le x \le 0 \cup 2 \le x \le 1 + \sqrt 3 \)     

\(1 - \sqrt 3  \le x \le 0 \cap 2 \le x \le 1 + \sqrt 3 \)

\(\dfrac{{ - 8}}{5}\)

\(3\)     

\(\dfrac{8}{5}\)           

\(\dfrac{{12}}{5}\)

\(\left( { - \dfrac{2}{3}; + \infty } \right)\)

\(\left( { - \infty ;0} \right)\)   

\(\left( { - \infty ; - \dfrac{2}{3}} \right)\)    

\(\left( {0; + \infty } \right)\backslash \left\{ 1 \right\}\)