Cho $\Delta ABC$ có AB = AC và  MB = MC ($M \in BC$).Chọn câu sai.

$AB = MN$ 

$AC = NP$   

$\widehat A = \widehat M$ 

$\widehat P = \widehat C$

50$^\circ$

40$^\circ$

70$^\circ$

80$^\circ$

$\widehat D = 33^\circ$ 

$\widehat D = 42^\circ$   

$\widehat E = 32^\circ$ 

$\widehat D = 66^\circ$

$\Delta ABC = \Delta CDA$

$\widehat {ABC} = \widehat {CDA}$        

$\widehat {BAC} = \widehat {DAC}$        

$\widehat {BCA} = \widehat {DAC}$

$\widehat A = \widehat D = 65^\circ ;\,\widehat C\, = \widehat F = 50^\circ .$

$\widehat A = \widehat D = 50^\circ ;\,\widehat C\, = \widehat F = 65^\circ .$ 

$\widehat A = \widehat D = 75^\circ ;\,\widehat C\, = \widehat F = 50^\circ .$ 

$\widehat A = \widehat D = 50^\circ ;\,\widehat C\, = \widehat F = 75^\circ .$

$\Delta ABC = \Delta DEF$ 

$\Delta ABC = \Delta EFD$   

$\Delta ABC = \Delta FDE$ 

$\Delta ABC = \Delta DFE$