Cho các vectơ $\overrightarrow u = \left( {{u_1};{u_2}} \right),{\rm{ }}\overrightarrow v  = \left( {{v_1};{v_2}} \right)$. Điều kiện để vectơ $\overrightarrow u \, = \overrightarrow v $ là

\(\left( {i;j} \right)\)

\(\left( {\overrightarrow i ;\overrightarrow j } \right)\)

\(\left( {\overrightarrow m ;\overrightarrow n } \right)\)

\(\left( {m;n} \right)\)

\(\overrightarrow u  =  - \overrightarrow i \)

\(\overrightarrow u  =  - \overrightarrow j \)

\(\overrightarrow u  = \overrightarrow i \)

\(\overrightarrow u  = \overrightarrow j \)

$\overrightarrow {AB}  = \left( {{y_A} - {x_A};{y_B} - {x_B}} \right)$.

$\overrightarrow {AB}  = \left( {{x_A} + {x_B};{y_A} + {y_B}} \right)$

$\overrightarrow {AB}  = \left( {{x_A} - {x_B};{y_A} - {y_B}} \right)$.

$\overrightarrow {AB}  = \left( {{x_B} - {x_A};{y_B} - {y_A}} \right)$.

\(\overrightarrow {OM}  = \left( { - 3; - 1} \right)\)

\(\overrightarrow {OM}  = \left( {3;1} \right)\)         

\(\overrightarrow {MO}  = \left( { - 3;1} \right)\)

\(\overrightarrow {OM}  = \left( { - 3;1} \right)\)

$\left( {2;4} \right)$.

$\left( {5;6} \right)$.

$\left( {15;10} \right)$.

$\left( {50;6} \right)$.

\(\overrightarrow {OM}  =  - 2\overrightarrow i  + 4\overrightarrow j \)

\(\overrightarrow {OM}  = 2\overrightarrow i  - 4\overrightarrow j \)

\(\overrightarrow {OM}  = 2\overrightarrow j  - 4\overrightarrow i \)

\(\overrightarrow {OM}  =  - 2\overrightarrow i  - 4\overrightarrow j \)