Cho $\overrightarrow a ,\overrightarrow b$ là các VTCP của mặt phẳng $\left( P \right)$

. Chọn kết luận sai?

 

 

$- \overrightarrow a$ hoặc $- \overrightarrow b$

$\left[ {\overrightarrow a ,\overrightarrow b } \right]$    

$\overrightarrow a  - \overrightarrow b$

$\overrightarrow a  + \overrightarrow b$

$\left( {1;2;0} \right)$

$\left( {2;11; - 7} \right)$

$\left( {4; - 22; - 14} \right)$

$\left( {2;2; - 4} \right)$

$a\left( {x - {x_0}} \right) + b\left( {y - {y_0}} \right) + c\left( {z - {z_0}} \right) = 0$      

${x_0}\left( {x - a} \right) + {y_0}\left( {y - b} \right) + {z_0}\left( {z - c} \right) = 0$

$x\left( {a - {x_0}} \right) + y\left( {b - {y_0}} \right) + z\left( {c - {z_0}} \right) = 0$       

$a\left( {x + {x_0}} \right) + b\left( {y + {y_0}} \right) + c\left( {z + {z_0}} \right) = 0$

$\overrightarrow n  = \left( {a;b;c;d} \right)$

$\overrightarrow n  = \left( {{a^2};{b^2};{c^2}} \right)$

$\overrightarrow n  = \left( {a + b;b + c;c + a} \right)$

$\overrightarrow n  = \left( {a;b;c} \right)$

$\left( {a;b;c} \right)$           

$\left( {a; - b; - c} \right)$

$\left( { - a; - b; - c} \right)$

$\left( {a; - b; - c; - d} \right)$

$\left( {2; - 1;1} \right)$

$\left( {2;0; - 1} \right)$

$\left( {2;0;1} \right)$

$\left( {2; - 1;0} \right)$