Biết: \(\left| {\dfrac{{\rm{3}}}{{\rm{4}}}{\rm{x}} - \dfrac{{\rm{1}}}{{\rm{2}}}} \right| - \dfrac{{\rm{1}}}{{\rm{2}}} = \dfrac{{\rm{1}}}{{\rm{4}}}\) khi đó \(x\) nhận các giá trị là:
Trả lời bởi giáo viên
\(\left| {\dfrac{{\rm{3}}}{{\rm{4}}}{\rm{x}} - \dfrac{{\rm{1}}}{{\rm{2}}}} \right| - \dfrac{{\rm{1}}}{{\rm{2}}} = \dfrac{{\rm{1}}}{{\rm{4}}}\)
\(\left| {\dfrac{{\rm{3}}}{{\rm{4}}}{\rm{x}} - \dfrac{{\rm{1}}}{{\rm{2}}}} \right| = \dfrac{{\rm{1}}}{{\rm{4}}} + \dfrac{{\rm{1}}}{{\rm{2}}}\)
\(\left| {\dfrac{{\rm{3}}}{{\rm{4}}}{\rm{x}} - \dfrac{{\rm{1}}}{{\rm{2}}}} \right| = \dfrac{{\rm{1}}}{{\rm{4}}} + \dfrac{{\rm{2}}}{{\rm{4}}}\)
\(\left| {\dfrac{{\rm{3}}}{{\rm{4}}}{\rm{x}} - \dfrac{{\rm{1}}}{{\rm{2}}}} \right| = \dfrac{{\rm{3}}}{{\rm{4}}}\)
TH1: \(\dfrac{{\rm{3}}}{{\rm{4}}}{\rm{x}} - \dfrac{{\rm{1}}}{{\rm{2}}} = \dfrac{{\rm{3}}}{{\rm{4}}}\)
\(\dfrac{{\rm{3}}}{{\rm{4}}}{\rm{x}} = \dfrac{{\rm{3}}}{{\rm{4}}} + \dfrac{{\rm{1}}}{{\rm{2}}}\)
\(\dfrac{{\rm{3}}}{{\rm{4}}}{\rm{x}} = \dfrac{{\rm{3}}}{{\rm{4}}} + \dfrac{{\rm{2}}}{{\rm{4}}}\)
\(\dfrac{{\rm{3}}}{{\rm{4}}}{\rm{x}} = \dfrac{{\rm{5}}}{{\rm{4}}}\)
\({\rm{x}} = \dfrac{{\rm{5}}}{{\rm{4}}}{\rm{:}}\dfrac{{\rm{3}}}{{\rm{4}}}\)
\({\rm{x}} = \dfrac{{\rm{5}}}{{\rm{4}}}{\rm{.}}\dfrac{{\rm{4}}}{{\rm{3}}}\)
\({\rm{x}} = \dfrac{{\rm{5}}}{{\rm{3}}}\)
TH2: \(\dfrac{{\rm{3}}}{{\rm{4}}}{\rm{x}} - \dfrac{{\rm{1}}}{{\rm{2}}} = \dfrac{{ - {\rm{3}}}}{{\rm{4}}}\)
\(\dfrac{{\rm{3}}}{{\rm{4}}}{\rm{x}} = \dfrac{{ - {\rm{3}}}}{{\rm{4}}} + \dfrac{{\rm{1}}}{{\rm{2}}}\)
\(\dfrac{{\rm{3}}}{{\rm{4}}}{\rm{x}} = \dfrac{{ - {\rm{3}}}}{{\rm{4}}} + \dfrac{{\rm{2}}}{{\rm{4}}}\)
\(\dfrac{{\rm{3}}}{{\rm{4}}}{\rm{x}} = \dfrac{{ - {\rm{1}}}}{{\rm{4}}}\)
\({\rm{x}} = \dfrac{{ - {\rm{1}}}}{{\rm{4}}}{\rm{:}}\dfrac{{\rm{3}}}{{\rm{4}}}\)
\({\rm{x}} = \dfrac{{ - {\rm{1}}}}{{\rm{4}}}{\rm{.}}\dfrac{{\rm{4}}}{{\rm{3}}}\)
\({\rm{x}} = \dfrac{{ - {\rm{1}}}}{{\rm{3}}}\)
Hướng dẫn giải:
- Muốn tìm số bị trừ ta lấy hiệu cộng với số trừ.
- Lưu ý: \(|A| = B\,\left( {B > 0} \right)\)
Suy ra \(A = B\) hoặc \(A = - B.\)