Viết pt phản ứng theo chuỗi biến hoá sau :

a. HCL-CL2-NaCl-HCL-CuCL-AgCL-Ag

b.CL2-HCL-AgCL-CL2-Br2-I2

C.MnO2-CL2-KCLO3-KCL-HCL-CL2-CaOCL2

Mình trả lời phần b nhé

Nhiều quá ọ

Đáp án + Giải thích các bước giải:

$a)$

$MnO_2+4HCl\to MnCl_2+Cl_2\uparrow+2H_2O$

$Cl_2+2NaOH\to NaCl+NaClO+H_2O$

$2NaCl+H_2SO_4\xrightarrow{>400^oC}2HCl+Na_2SO_4$

$CuO+2HCl\to CuCl_2+H_2O$

$CuCl_2+2AgNO_3\to Cu(NO_3)_2+2AgCl\downarrow$

$2AgCl\xrightarrow{\text{ánh sáng}}2Ag+Cl_2\uparrow$

$b)$

$Cl_2+H_2O\leftrightharpoons HCl+HClO$

$AgNO_3+HCl\to AgCl\downarrow+HNO_3$

$2AgCl\xrightarrow{\text{ánh sáng}}2Ag+Cl_2\uparrow$

$Cl_2+2HBr\to 2HCl+Br_2$

$Br_2+2HI\to 2HBr+I_2$

$c)$

$MnO_2+4HCl\to MnCl_2+Cl_2\uparrow+2H_2O$

$3Cl_2+6KOH\xrightarrow{t^o}5KCl+KClO_3+3H_2O$

$2KClO_3\xrightarrow[MnO_2]{t^o}2KCl+3O_2\uparrow$

$2KCl+H_2SO_4\xrightarrow{500^oC}2HCl+K_2SO_4$

$2KMnO_4+16HCl\to 2KCl+2MnCl_2+5Cl_2\uparrow+8H_2O$

$Cl_2+Ca(OH)_2\to CaOCl_2+H_2O$