1 câu trả lời
$\left|x-2\right|=2x-1\Leftrightarrow \orpt{\begin{matrix}x-2=2x-1\left(x\ge 2\right)\\2-x=2x-1\left(x<2\right)\end{matrix}}\Leftrightarrow \orpt{\begin{matrix}x=-1\left(x\ge 2\right)\\x=1\left(x<2\right)\end{matrix}}$
$\Rightarrow S=x_1+x_2=0+1=1$
