Tính mol của: a) 2,4 gam Mg; 9,8 gam CuSO4; 14,8 gam Ca(OH)2 b) 4,48 lit H2; 8,96 lit CO2; 13,44 lit N2 (đktc) Câu 2: Tính thể tích chất khí ở đktc của: a) 0,1 mol O2; 0,5 mol N2; 1,25 mol SO3 b) 22 gam CO2; 7 gam N2; 2 gam H2. c) Hỗn hợp gồm 0,2 mol O2; 0,3 mol Cl2 d) Hỗn hợp gồm 1 gam H2; 8 gam O2

Câu 1:

$a,n_{Mg}=\dfrac{m}{M}=\dfrac{2,4}{48}=0,05(mol)\\ n_{CuSO_4}=\dfrac{m}{M}=\dfrac{9,8}{160}=0,06125(mol)\\ n_{Ca(OH)_2}=\dfrac{m}{M}=\dfrac{14,8}{74}=0,2(mol)\\ b,n_{H_2}=\dfrac{V}{22,4}=\dfrac{4,48}{22,4}=0,2(mol)\\ n_{CO_2}=\dfrac{V}{22,4}=\dfrac{8,96}{22,4}=0,4(mol)\\ n_{N_2}=\dfrac{V}{22,4}=\dfrac{13,44}{22,4}=0,6(mol)$

Câu 2:

$a,V_{O_2}=n.22,4=0,1.22,4=2,24(l)\\ V_{N_2}=0,5.22,4=11,2(l)\\ V_{SO_3}=1,25.22,4=28(l)\\ b,n_{CO_2}=\dfrac{22}{44}=0,5(mol)\\ \Rightarrow V_{CO_2}=0,5.22,4=11,2(l)\\ n_{N_2}=\dfrac{7}{28}=0,25(mol)\\ \Rightarrow V_{N_2}=0,25.22,4=5,6(l)\\ n_{H_2}=\dfrac{2}{2}=1(mol)\\ \Rightarrow V_{H_2}=1.22,4=22,4(l)\\ c,V_{hh}=V_{O_2}+V_{Cl_2}=0,2.22,4+0,3.22,4=11,2(l)\\ d,n_{H_2}=\dfrac{1}{2}=0,5(mol);n_{O_2}=\dfrac{8}{32}=0,25(mol)\\ \Rightarrow V_{hh}=V_{H_2}+V_{O_2}=0,5.22,4+0,25.22,4=16,8(l)$