Tìm x, biết: a) x . (x – 2) = 0; b) (x – 1) . (x + 5) = 0; c) (x – 3)2 = 0.

Đáp án+Giải thích các bước giải:

`a)x.(x-2)=0`

`=>` \(\left[ \begin{array}{l}x=0\\x-2=0\end{array} \right.\)

`=>` \(\left[ \begin{array}{l}x=0\\x=2\end{array} \right.\)

`to` Vậy `x∈{0;2}`

`b)(x-1).(x+5)=0`

`=>` \(\left[ \begin{array}{l}x-1=0\\x+5=0\end{array} \right.\)

`=>` \(\left[ \begin{array}{l}x=0+1\\x=0-5\end{array} \right.\)

`=>` \(\left[ \begin{array}{l}x=1\\x=-5\end{array} \right.\) 

`to` Vậy `x∈{1;-5}` 

`c)(x-3)2=0`

`=>(x-3)=0:2`

`=>x-3=0`

`=>x=0+3`

`=>x=3`

`to` Vậy `x=3`

`a ) x . ( x - 2) = 0`

`=>`\(\left[ \begin{array}{l}x=0\\x-2 = 0\end{array} \right.\)

`=>`\(\left[ \begin{array}{l}x=0\\x = 2\end{array} \right.\) 

Vậy `x ∈ {0 ; 2}`

`b ) (x - 1).(x + 5) = 0`

`=>`\(\left[ \begin{array}{l}x-1=0\\x+ 5 = 0\end{array} \right.\)

`=>`\(\left[ \begin{array}{l}x=1\\x = -5\end{array} \right.\) 

Vậy `x ∈ {1 ; -5}`

`c ) (x-3).2 = 0`

`=> x - 3 = 0 . 2`

`=> x - 3 = 0`

`=> x = 0 + 3`

`=> x = 3`

Vậy `x = 3`

`#dtkc`