Tìm x biết: 2021^2022 . ( 125^3 . 7^5 - 175^5 : 5 ) + 2x = 6

Đáp án:

`x=3.`

Giải thích các bước giải:

`2021^2022 . ( 125^3 . 7^5 - 175^5 : 5 ) + 2x = 6`

`=>2021^2022 . ((5^3)^3 . 7^5-(5^2 . 7)^5:5)+2x=6`

`=>2021^2022 . (5^(3 . 3) . 7^5-5^(2 . 5) . 7^(1 . 5):5)+2x=6`

`=>2021^2022 . (5^9 . 7^5-5^10 . 7^5:5)+2x=6`

`=>2021^2022 . [5^9 . 7^5-(5^10:5) . 7^5)+2x=6`

`=>2021^2022 . [5^9 . 7^5-(5^(10-1)) . 7^5]+2x=6`

`=>2021^2022 . (5^9 . 7^5-5^9 . 7^5)+2x=6`

`=>2021^2022 . [(5^9-5^9)+(7^5-7^5)]+2x=6`

`=>2021^2022 . [(5^(9-9))+(7^(5-5))]+2x=6`

`=>2021^2022 . (5^0+7^0)+2x=6`

`=>2021^2022 . (0+0)+2x=6`

`=>2021^2022 . 0+2x=6`

`=>(2021^2022 . 0)+2x=6`

`=>0+2x=6`

`=>2x=6`

`=>x=6:2`

`=>x=6/2`

`=>x=3.`