Tìm nồng độ mol của các chất sau: 500ml dung dịch A chứa 19,88g Na2So4 200ml dung dịch B chứa 16g CuSo4

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Công thức tính nồng độ mol:

${C_M} = \dfrac{n}{V}$

- Dung dịch A:

$ {n_{N{a_2}S{O_4}}} = \dfrac{{19,88}}{{142}} = 0,14\,\,mol$

$   \to {C_{M\,\,N{a_2}S{O_4}}} = \dfrac{{0,14}}{{0,5}} = 0,28M $

- Dung dịch B:

$  {n_{Cu\,S{O_4}}} = \dfrac{{16}}{{160}} = 0,1\,\,mol $

$   \to {C_{M\,\,Cu\,S{O_4}}} = \dfrac{{0,1}}{{0,2}} = 0,5M $

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