2 câu trả lời
`ab + a = -15`
`<=> a . b + a . 1 = -15`
`<=> a . ( b + 1 )`
Mà `Ư(15 ) = { - 15 ; -5 ; -3 ; -1 ; 1 ; 3 ; 5 ; 15 }`
Ta có bảng :
\begin{array}{|c|c|c|}\hline \text{a}&\text{-15}&\text{-5}&\text{-3}&\text{-1}&\text{1}&\text{3}&\text{5}&\text{15}\\\hline \text{b + 1}&\text{1}&\text{3}&\text{5}&\text{15}&\text{-15}&\text{-5}&\text{-3}&\text{-1}\\\hline \text{b}&\text{0}&\text{2}&\text{4}&\text{14}&\text{-16}&\text{-6}&\text{-4}&\text{-2}\\\hline\end{array}
Vậy các cặp ` ( a ; b )` thảo mãn là : ....
Đáp án:
`↓`
Giải thích các bước giải:
`ab + a = -15`
`=> a * b + a * 1 = -15`
`=> a * ( b + 1 ) = -15`
`=> a; b + 1 \in Ư(-15) = { -15; -5; -3; -1; 1; 3; 5; 15 }`
Ta có bảng:
$\begin{array}{|c|c|c|}\hline \text{a}&\text{-15}&\text{-5}&\text{-3}&\text{-1}&\text{1}&\text{3}&\text{5}&\text{15}\\\hline \text{b + 1}&\text{1}&\text{3}&\text{5}&\text{15}&\text{-15}&\text{-5}&\text{-3}&\text{-1}\\\hline \text{b}&\text{0}&\text{2}&\text{4}&\text{14}&\text{-16}&\text{-6}&\text{-4}&\text{-2}\\\hline\end{array}$
Vậy ...
`#Sad`