Hứa 5 sao và ctlhn. Mary paid $287 for 2 handbags and 5 blouses. On average, a handbag cost $42 more than a blouse. How much did she pay for the 5 blouses?
2 câu trả lời
$We have:2xhandbags+5xblouses=287$
$Handbag-Blouse=42=>Handbag=Blouse +42$
$We have:2x(blouse +42)+5blouses=287$
$=>2blouses+84+5blouses=287$
$=>7blouses=-287-84=203$
$=>1Blouse:203:7=29$
Therefore,the price of 5 blouses is computed as below: $29x5=145$
We have: 2 x handbags + 5 x blouses = 287 (1)
Handbag - Blouse = 42 => Handbag = Blouse + 42
We have: (1) ⇔ 2 x (blouse +42) + 5 blouses = 287
⇔ 2 blouses + 84 + 5 blouses = 287
⇔ 7 blouses = 287 - 84 = 203
⇔ 1 Blouse = 203 : 7 = 29
Therefore, the price of 5 blouses is computed as below:
29 x 5 = 145