Hứa 5 sao và ctlhn. Mary paid $287 for 2 handbags and 5 blouses. On average, a handbag cost $42 more than a blouse. How much did she pay for the 5 blouses?

2 câu trả lời

$We have:2xhandbags+5xblouses=287$

$Handbag-Blouse=42=>Handbag=Blouse +42$

$We have:2x(blouse +42)+5blouses=287$

$=>2blouses+84+5blouses=287$

$=>7blouses=-287-84=203$

$=>1Blouse:203:7=29$

Therefore,the price of 5 blouses is computed as below: $29x5=145$

We have: 2 x handbags + 5 x blouses = 287 (1)

Handbag - Blouse = 42 => Handbag = Blouse + 42

We have: (1) ⇔ 2 x (blouse +42) + 5 blouses = 287

⇔ 2 blouses + 84 + 5 blouses = 287

⇔ 7 blouses = 287 - 84 = 203

⇔ 1 Blouse = 203 : 7 = 29

Therefore, the price of 5 blouses is computed as below:

29 x 5 = 145 

Câu hỏi trong lớp Xem thêm