Hoàn thành chuỗi phản ứng sau MnO2 -> Cl2 -> HCl -> NaCl -> Cl2 Cl2 -> haven -> NaHCO3 Cl2 -> clorua vôi -> CaCO3 Cl2 -> Kali clorat -> Cl2

Đáp án:

`↓`

Giải thích các bước giải:

`-` 

`+` `MnO_2``+``4HCl``→``MnCl_2``+``Cl_2↑``+``2H_2O`

`+` `Cl_2``+``H_2` $\xrightarrow[]{as}$ `2HCl`

`+` `HCl``+``NaOH``→``NaCl``+``H_2O`

`+` `2NaCl` $\xrightarrow[]{đpnc}$ `2Na``+``Cl_2↑`

`-`

`+` `Cl_2``+``2NaOH``→``NaClO``+``NaCl``+``H_2O`

`+` `NaClO``+``CO_2``+``H_2O``→``NaHCO_3``+``HClO`

`-`

`+` `3Cl_2``+`$6KOH_{đặc, nóng}$ $\xrightarrow[]{t^o}$ `KClO_3``+``5KCl``+``3H_2O`

`+` `KClO_3``+``6HCl``→``KCl``+``3Cl_2↑``+``3H_2O`

$\textit{Dãy 1:}$

`1) MnO_2 + 4HCl_{Đặc}` $\xrightarrow[]{Đun nhẹ}$ `MnCl_2 + Cl_2↑ + 2H_2O`

`2) Cl_2 + H_2` $\xrightarrow[]{t^o}$`2HCl↑`

`3) HCl + NaOH -> NaCl + H_2O`

`4) 2NaCl + 2H_2O` $\xrightarrow[Có màng ngăn]{Điện phân dung dịch}$ `2NaOH + H_2↑ + Cl_2↑`

$\textit{Dãy 2:}$

`1) Cl_2 + 2NaOH -> NaCl + NaClO + H_2O`

`2) NaClO + H_2O + CO_2 -> NaHCO_3 + HClO`

$\textit{Dãy 3:}$

`1) Cl_2 + Ca(OH)_2 -> CaOCl_2 + H_2O`

`2) 2CaOCl_2 + H_2O + CO_2 -> CaCO_3 + CaCl_2 + 2HClO`

$\textit{Dãy 4:}$

`1) 3Cl_2 + 6KOH_{Đặc}` $\xrightarrow[]{t^o}$ `5KCl + KClO_3 + 3H_2O`

`2) KClO_3 + 6HCl -> 3Cl_2↑ + KCl + 3H_2O`