Cho e hỏi (m-1)×(3m-16)》0

Đáp án:$m \ge \frac{{16}}{3}\,hoặc\,m \le 1$

Giải thích các bước giải:

$\begin{array}{l} \left( {m - 1} \right)\left( {3m - 16} \right) \ge 0\\  \Leftrightarrow \left[ \begin{array}{l} \left\{ \begin{array}{l} m - 1 \ge 0\\ 3m - 16 \ge 0 \end{array} \right.\\ \left\{ \begin{array}{l} m - 1 \le 0\\ 3m - 16 \le 0 \end{array} \right. \end{array} \right. \Leftrightarrow \left[ \begin{array}{l} \left\{ \begin{array}{l} m \ge 1\\ m \ge \frac{{16}}{3} \end{array} \right.\\ \left\{ \begin{array}{l} m \le 1\\ m \le \frac{{16}}{3} \end{array} \right. \end{array} \right. \Leftrightarrow \left[ \begin{array}{l} m \ge \frac{{16}}{3}\\ m \le 1 \end{array} \right. \end{array}$

Vậy $m \ge \frac{{16}}{3}\,hoặc\,m \le 1$