Cacbon có 2 đồng vị bền. Đồng vị thứ nhất có 6 proton, 7 notron, chiếm 1,11%. Đồng vị thứ hai có ít hơn đồng vị thứ nhất 1 notron. a. Viết kí hiệu nguyên tử C b. Viết nguyên tử khối trung bình của C? Giúp em với ạ! :3

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Đồng vị thứ nhất có nguyên tử tử khối là 6+7=13

Đồng vị thứ 2 có 7-1=6 notron -> nguyên tử khối là 12

a) 6C12; 6C13

b) -> NTK trung bình =13.1,11%+12.(100%-1,11%)=12,0111 (đvC)

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