2 câu trả lời
Answer
`4 . (x - 1/2)^2 - 1 = 0`
`=> 4 . (x - 1/2)^2 = 0 + 1`
`=> 4 . (x - 1/2)^2 = 1`
`=> (x - 1/2)^2 = 1 : 4`
`=> (x - 1/2)^2 = 1/4`
`=> (x - 1/2)^2 = (+-1/2)^2`
`=>` $\left[\begin{matrix} x - \dfrac{1}{2} = \dfrac{1}{2}\\ x - \dfrac{1}{2} = \dfrac{-1}{2}\end{matrix}\right.$
`=>` $\left[\begin{matrix} x = \dfrac{1}{2} + \dfrac{1}{2}\\ x = \dfrac{-1}{2} + \dfrac{1}{2}\end{matrix}\right.$
`=>` $\left[\begin{matrix} x = 1\\ x = 0\end{matrix}\right.$
Vậy `x \in {1 ; 0}`
$\text{4(x - $\dfrac{1}{2}$)² - 1 = 0}$
$\text{4(x - $\dfrac{1}{2}$)² = 1}$
$\text{(x - $\dfrac{1}{2}$)² = $\dfrac{1}{4}$}$
$\text{(x - $\dfrac{1}{2}$)² = (±$\dfrac{1}{2}$)²}$
$\text{⇒ x - $\dfrac{1}{2}$ = ± $\dfrac{1}{2}$}$
$\text{⇒ x - $\dfrac{1}{2}$ = $\dfrac{1}{2}$ hoặc x - $\dfrac{1}{2}$ = -$\dfrac{1}{2}$}$
$\text{TH1: x - $\dfrac{1}{2}$ = $\dfrac{1}{2}$}$
$\text{x = $\dfrac{1}{2}$ + $\dfrac{1}{2}$}$
$\text{x = $\dfrac{1 + 1}{2}$}$
$\text{x = $\dfrac{2}{2}$}$
$\text{x = 1}$
$\text{TH2: x - $\dfrac{1}{2}$ = -$\dfrac{1}{2}$}$
$\text{x = -$\dfrac{1}{2}$ + $\dfrac{1}{2}$}$
$\text{x = $\dfrac{-1 + 1}{2}$}$
$\text{x = $\dfrac{0}{2}$}$
$\text{x = 0}$
$\text{Vậy x ∈ {0; 1}}$
$\textit{Ha1zzz}$