4 · (x-1/2) ² -1 = 0

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Answer

`4 . (x - 1/2)^2 - 1 = 0`

`=> 4 . (x - 1/2)^2 = 0 + 1`

`=> 4 . (x - 1/2)^2 = 1`

`=> (x - 1/2)^2 = 1 : 4`

`=> (x - 1/2)^2 = 1/4`

`=> (x - 1/2)^2 = (+-1/2)^2`

`=>` $\left[\begin{matrix} x - \dfrac{1}{2} = \dfrac{1}{2}\\ x - \dfrac{1}{2} = \dfrac{-1}{2}\end{matrix}\right.$

`=>` $\left[\begin{matrix} x = \dfrac{1}{2} + \dfrac{1}{2}\\ x = \dfrac{-1}{2} + \dfrac{1}{2}\end{matrix}\right.$

`=>` $\left[\begin{matrix} x = 1\\ x = 0\end{matrix}\right.$

Vậy `x \in {1 ; 0}`

$\text{4(x - $\dfrac{1}{2}$)² - 1 = 0}$

$\text{4(x - $\dfrac{1}{2}$)² = 1}$

$\text{(x - $\dfrac{1}{2}$)² = $\dfrac{1}{4}$}$

$\text{(x - $\dfrac{1}{2}$)² = (±$\dfrac{1}{2}$)²}$

$\text{⇒ x - $\dfrac{1}{2}$ = ± $\dfrac{1}{2}$}$

$\text{⇒ x - $\dfrac{1}{2}$ = $\dfrac{1}{2}$ hoặc x - $\dfrac{1}{2}$ = -$\dfrac{1}{2}$}$

$\text{TH1: x - $\dfrac{1}{2}$ = $\dfrac{1}{2}$}$

$\text{x = $\dfrac{1}{2}$ + $\dfrac{1}{2}$}$

$\text{x = $\dfrac{1 + 1}{2}$}$

$\text{x = $\dfrac{2}{2}$}$

$\text{x = 1}$

$\text{TH2: x - $\dfrac{1}{2}$ = -$\dfrac{1}{2}$}$

$\text{x = -$\dfrac{1}{2}$ + $\dfrac{1}{2}$}$

$\text{x = $\dfrac{-1 + 1}{2}$}$

$\text{x = $\dfrac{0}{2}$}$

$\text{x = 0}$

$\text{Vậy x ∈ {0; 1}}$

$\textit{Ha1zzz}$

 

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